Modulus / Mod / % operator in C Programming
% OPERATOR IN C :
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-> % OPERATOR is to get the remainder when a number is divided with any other number.
Example: int a=10%2; then the a value is zero. because the when 10 is divided by 2
the remainder is zero.
int a=10%2; Here 10 is numerator and 2 is denominator.
-> When the numerator is less than the denominator, then the result of the % operator is
numerator value.
Example: int a=2%10; Here the numerator 2 is less than the denominator 10. Hence
a value will be 2.
-> We cannot apply mod % operator on the floating values. It will generate compile time
error.
-> There is a special function ” fmod() ” for applying % operation on float.
-> Whenever we are performing mod % operation on any two operands then the resultant
sign is equivalent to numerator sign.
int a=-10%3; Then the result is a=-1 as the sign of numerator
10 is negative.
Examples to understand the operation of % operator:
1) int a=1%10;
printf(“%d”,a);
output:1
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2) int a=2%10;
printf(“%d”,a);
output:2
————————–
3) int a=3%10;
printf(“%d”,a);
output:3
————————–
4) int a=10%3;
printf(“%d”,a);
output:1
————————–
5) int a=10%4;
printf(“%d”,a);
output:2
—————————
6)int a=10%2;
printf(“%d”,a);
output:0
—————————
7) int a=-10%3;
printf(“%d”,a);
output:-1
————————-
8) int a=10.0%3;
printf(“%d”,a);
output: Error. As % operator cannot be applied on float.
————————–
9) int a= -10%-3;
printf(“%d”,a);
output: -1
(As the result sign is same as numerator sign)
——————————
10) int a=10%3.0;
printf(“%d”,a);
output: Error.As 3.0 is float and cannot be used in
% operation.
———————————–
-> % OPERATOR is to get the remainder when a number is divided with any other number.
Example: int a=10%2; then the a value is zero. because the when 10 is divided by 2
the remainder is zero.
int a=10%2; Here 10 is numerator and 2 is denominator.
-> When the numerator is less than the denominator, then the result of the % operator is
numerator value.
Example: int a=2%10; Here the numerator 2 is less than the denominator 10. Hence
a value will be 2.
-> We cannot apply mod % operator on the floating values. It will generate compile time
error.
-> There is a special function ” fmod() ” for applying % operation on float.
-> Whenever we are performing mod % operation on any two operands then the resultant
sign is equivalent to numerator sign.
int a=-10%3; Then the result is a=-1 as the sign of numerator
10 is negative.
Examples to understand the operation of % operator:
1) int a=1%10;
printf(“%d”,a);
output:1
————————-
2) int a=2%10;
printf(“%d”,a);
output:2
————————–
3) int a=3%10;
printf(“%d”,a);
output:3
————————–
4) int a=10%3;
printf(“%d”,a);
output:1
————————–
5) int a=10%4;
printf(“%d”,a);
output:2
—————————
6)int a=10%2;
printf(“%d”,a);
output:0
—————————
7) int a=-10%3;
printf(“%d”,a);
output:-1
————————-
8) int a=10.0%3;
printf(“%d”,a);
output: Error. As % operator cannot be applied on float.
————————–
9) int a= -10%-3;
printf(“%d”,a);
output: -1
(As the result sign is same as numerator sign)
——————————
10) int a=10%3.0;
printf(“%d”,a);
output: Error.As 3.0 is float and cannot be used in
% operation.